[mythwarden]

This is an old one to start with...


---------
"I never was, am always to be,
No one ever saw me, nor ever will
And yet I am the confidence of all
To live and breathe on this terrestrial ball."

[Giant Hamster]

You are Air! wheeeeeeeee *poop*

Anyways, not a riddle, but I liked it still:

If you weren't a man, my father too...
...I'd buy a ring and marry you.

[Rat]

Daughter...I know it wasn't really a riddle

Hmm...a riddle...*thinks*

Coaster, I think you know this one...I've told it to you at least once...DON'T ANSWER!!

Angry and hungry are two words that end in "gry". There are three words in the English language. What is the third word? We all know it, and we all use it every day.

[Jezebel]

Rat - Bwahaha.... I hate that riddle! I remember the first time I heard it, it drove me insane.

Since i know the answer I won't reveal it

[xXxPZxXx]

Rat- 3 words in "the english language" The third one would be language? Had me think for much too long on that one but then I remember one that my dad used to say.

Railroad crossing look out for the cars can you spell that without any r's?

of course you can... t-h-a-t

Dumb little rhyme and it was cool when I was 6 years old.

anyone played the game mindtrap? I will go try and find my box and post a few fun ones.

-PZ-

[Rat]

Yep...ya got it.

I've got a little book thing of riddles somewhere. I'll have to go find it.

Oh, and it just dawned on me that the answer I gave to Hamster's little semi-riddle was wrong...it's son, not daughter. *smacks forhead*

[ May 12, 2002: Message edited by: Rat ]

[Jezebel]

Mind Trap is a cool game.... I have a copy around somewhere.

[Vesuvius]

giant hamster- I think you're wrong with your answer- I think the correct answer to the first riddle is : the future. after all the clue says "I never was" - air was and continues to be. it exists. it also says no one saw it or EVER WILL- because the future is forever ahead. that's my answer anyways.

[Coaster]

Why did the chicken that needed to get to the other side of the road cross the road?

errr.....
nevermind.
/me isn't good at telling riddles

What row of numbers comes next?
1
11
21
1211
111221
312211
13112221

There is a common English word that is nine letters long. Each time you remove a letter from it, it still remains an English word - from nine letters right down to a single letter. What is the original word, and what are the words that it becomes after removing one letter at a time?

[Novacaptain]

The riddle of the sphinx:
What is the creature that walks on four legs in the morning, two legs at noon and three in the evening?

everyone probably knows this one, so just go ahead and answer it.

[edit] i think this one, though not too difficult, is a very nice one:

I come in darkness, but fill the mind with light.
I bring enlightenment to some, while gripping others in the hand of fear.
With me it can be a journey of inexplicable joy and sorrow.
What I will show you will often be unreachable.
Journey with me and what you see may haunt you.
Journey with me and you may never want to return home.
Journey with me and you will never know when it will end.

What am I?
[/edit]

[ May 12, 2002: Message edited by: Novacaptain ]

[mythwarden]

Hamster-

That's a great guess. Wrong...but still a good.

Vesuvius-

Very close, my friend. I'll give you a hint next time, if you haven't gotten it.


Novacaptain-

I'll not give away your ancient riddle that Oedipus answers.
Someone should try answering it without aid.

Coaster-

You got me thinking about your mathematical one now. I'll have to try next time if no one else has given it a shot. ;-)

-myth

[mythwarden]

Novacaptain- Didn't see the second riddle before...

"A Dream"

?

[Brain]

A man looking at a photo says:

"Brothers and sisters
of which I have none,
But this man's father
Is my father's son."

Another oldie but a goodie @:-)

[Pixie Nim]

Novacaptain - easy, the answer is a man. (I like riddles!) four legs in the morning - a baby crawling. two legs in the afternoon - a man walking. three legs in the evening - an old man with a walking stick!

Don't know about the second one, tho...

Brain - the answer is, he's looking at a photo of himself. Easy one, that...

Coaster - the answer is: 1113213211... that one was a bit tricky, and I'm not too good at maths... is it right?

okay, here's one for you:
Who makes it, has no need of it.
Who buys it, has no use for it.
Who uses it can neither see nor feel it.
What is it?

Pixie

[a_sh]

pixie nim: hmm... i believe he's looking at a picture of his son, not himself...

"Brothers and sisters
of which I have none,
But this man's father
Is my father's son."

line 1 and 2 means that line 4 is himself, but 'himself' is, according to line 3 the person in the picture's father...

ok, here's a silly one:
what goes up and down at the same time?

[Rat]

Pixie - It's a coffin, right?

Everyone probably knows this one:

When is a door not a door?

[Vesuvius]

when someone took it off it's hinges and made a table out of it!

or when it's ajar, but that's just lame.

[Novacaptain]

yep yep, you got mine right.
The first one is man
the second is your dreams

A_sh: a ladder or staircase maybe?

A man is captured by a bunch of crazy artists who decide to kill him (we all know that there isn't such a thing as cannibals). To make it more interesting they ask him to make a statement:
If it is true, they'll stab him to death with their wacom pens.
If false, they'll throw him off a large cliff onto a large white canvas several miles below.
The man is still alive today.
What did he say?

[ May 13, 2002: Message edited by: Novacaptain ]

[Awetopsy]

Novacaptain: he said "It would be more artistic if you stabbed yourselves with the wacom pens and jumped off the cliff"

they believed him because they were crazy remember.

[wayfinder]

novacaptain, i guess he said something like "this is a lie."

anyway,..


three people buy a game together that costs $30. everyone puts $10 in it. when they leave the store, the storekeeper notices that the game was on sale and $5 off. so he sends junior after the three with $5 (now we're entering the waters of fiction ). now junior is a bright little boy and thinks, "5 dollars for 3 people, that cannot be parted justly." so hecatches up with them, hands them $3 and keeps the rest for himself (obviously telling them the game was $3 off).

Ok, that's the story so far.

Now each of the three guys paid $9, right? that's $27. junior has $2, that makes 29. who has the remaining dollar?

[Hunago]

wayfinder, that question almost drives me crazy, the numbers sound so easy at first.. takes me 20 minutes with a piece of paper to figure it out.

evil question

[Kuku]

wayfinder, i get the feeling that its a trick question
what 1 dollar?
they paid 27 bux for a 25 dollar game, since junior kept the 2 dollars, adds up perfecly.

[wayfinder]

hehe

here's another one:

you have nine billard balls, one of which is a little bit heavier than the others, which are perfectly identical in every respect otherwise. you also have scales to check which one of two things is heavier. how can you, with only two scalings, detect the ball that's not normal?

and yet another one:

you have two fuses that you know burn 1 hour each. you also know that they do not burn at a constant rate. how can you measure 45 minutes with these two fuses?


AAAaand yet another one:

You have 6 boxes of needles, each containing a hundred pieces. through a production fault, one of he boxes contains needles that are a tiny bit heavier than normal, which would result in horrible, horrible tragedy if they were used. your task is to find out which box is the dangerously dangerous one with the heavy needles from hell.

you know what one needle is supposed to weigh. you have a digital scale, which is a korean production, so it works perfectly precise, but only once, then it's broken. (don't hit me too hard, i luv korea )

how do you go about, sherlock?

[Awetopsy]

quote

Quote:

you have two fuses that you know burn 1 hour each. you also know that they do not burn at a constant rate. how can you measure 45 minutes with these two fuses?

assuming both fuses are the same length, fold one fuse(a) in half and line up with one end of the other fuse(b).. burn other fuse(b) to same length as folded fuse(a). Unfold folded fuse(a) and take remainder of burnt fuse(b) and fold that in half... then line it up to one end of the previously folded(a) fuse and burn the previously folded(a) fuse to distance of now folded fuse(b). (hope that makes sense)

or if you are allowed to burn only 1 fuse, fold the other fuse in 1/2 twice, line up with 1 end of fuse you're gonna burn and burn from the opposite end.

[ May 17, 2002: Message edited by: Awetopsy ]

[Awetopsy]

quote:

---

Originally posted by wayfinder:
You have 6 boxes of needles, each containing a hundred pieces. through a production fault, one of he boxes contains needles that are a tiny bit heavier than normal, which would result in horrible, horrible tragedy if they were used. your task is to find out which box is the dangerously dangerous one with the heavy needles from hell.

you know what one needle is supposed to weigh. you have a digital scale, which is a korean production, so it works perfectly precise, but only once, then it's broken. (don't hit me too hard, i luv korea )

how do you go about, sherlock?

---

ok.. math is not my strong point... but here goes.

Label each box a, b, c, d, e, and f. take 1 needle from box a and put on top of box b. then take two from box a and put on box c, 3 from box a on box d, 4 on box e.... etc. do this on with each box of needles until you have something that looks like this:


the weight of each box is now 15 needles less than previously. and we will call that weight "z"

now we assign "x" to normal weight needles and "y" to heavier needles.

so pick a box, lets say we pick box f for ease-sake, and weigh it.

SOoOoOoOo.... here is the equation...

if the weight of the box with all the needles is z(being 15 less than a full box) + 14x(because there are 14 normal needles) + 1y (1 over weight needle) than the heavy box is Box "e"

if it is z + 13x + 2y than it is box "d"

if it is z + 12x + 3y than it is box "c"

if it is z + 11x + 4y than it is box "b"

if it is z + 10x + 5y than it is box "a"

if it is z + 15x + 0y than it is box "f"

I hope that all makes sense. Im terrible at describing math.

[Novacaptain]

Wayfinder: he says "I will be thrown off the cliff"

This creates a paradox, since if they were to throw him off the cliff, it would become a true statement.

And if they decide to stab him, the statement would become false. so they let him go...or maybe they shot him for being a smartass?

[Hunago]

Lol novacaptain.

wayfinder's questions are giving me headaches..
I figured out the 9 billard ball question. but not the other two.
Awetopsy, your anwer for the pins question is ingenious. It make lots of sense. I'm not sure whether the y value is given though. Like, we don't know how much heavier each overweight needles are..

Those aren't trick questions eh?

[vurx]

you have a 9 oz beaker and a 5 oz beaker and a sink with running water. your task is to precicely measure out 1 (one) oz of water.

the beekers have no other measuring lines besides the markings at their top. the containers are irregularly shaped as well.

how do you do it?

-=-=- and an easy one

there is a magic lilypad in the center of a pond. on day 1 it is 1.25 feet in diameter, everyday it doubles in size, on day 10 it covers the entire pond. on which day does it cover half of the pond?

[wayfinder]

Awetopsy: your solution to the fuses problem does not work, because they do not have constant burn rates, so if half of the length of a fuse has burned, it doesn't mean that half an hour has passed!

also, your solution to the needles is total overkill i was thinking about labeling the boxes 0 through 5 and putting from each box the number of needles that you wrote on the box on the scale. that would be your 15 needles, but we need only one set: cause if the weight is 15x+0y, it's box 0. if it's 15x+1y, it's box1, and so on.

additional question:
what do you do if you don't know how many (and if any) of the boxes contain needles of the weight x+y?


novacaptain: yes, i see that was a good one!


Hunago: You figured out the 9ball question? great! post the solution! and then solve it for 12 balls and three weighings, and you don't know whether the off ball weighs more or less!

vurx: i fill the 5 oz beaker and pour everything into the 9 oz beaker. then i fill the 5 oz beaker again and pour as much as will fit into the 9 oz beaker. since there were already 5 oz in it, 4 more will fit, leaving me with 1 oz in the 5 oz beaker.

the magic lilypad covers half the pond on day 9

[ May 17, 2002: Message edited by: wayfinder ]

[Hunago]

for the 9ball question;
divide the 9 balls into 3 groups of 3. Use the scale to weight any two groups.. then it branches off to two possibilities.

1)if one of the group is heavier. Divide that heavier group again and weight any 2 individual balls. if they are equal, the remaining ball is the heavier.

2)if the two groups of 3 are equal, then the remaining group has the heavier ball, divide it up and weight the same way.

For 12 balls, maybe a similiar method will work? Like dividing them into 3 groups 4... or 4 groups of 3...